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Cos 60=a/k 1/2=4.6/k. K=9.2m check answer because i am not sure
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length of the wall = AB = 7.96 m
BC = 4.6 m
AC = ?
by applying Pythagoras thereom
AC² = AB ² + BC²
AC² = 62.41 + 21.16
AC = √83.57
AC = 9.14 m
so the length of the ladder is 9.14 m
BC = 4.6 m
AC = ?
by applying Pythagoras thereom
AC² = AB ² + BC²
AC² = 62.41 + 21.16
AC = √83.57
AC = 9.14 m
so the length of the ladder is 9.14 m
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