If the sum of squares of LCM & HCF of two positive numbers is 3609 and their LCM is 57 more than their HCF, then the product of two number's is
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Let the HCF be x
Therefore, LCM = (x+57)
Sum of squares = x (to the power 2) + [(x+57)(to the power 2)
ATP, sum of squares = 3609
So, x(2) + [(x+57)(square)] = 3609
X(2)+x(2)=3609-3749
2x(square)=360
2x=(under root) 360
2x = 2*2*2*3*3*5
2x = 2*3
2x = 6
X = 6/2
X = 3.
Therefore, HCF = 3
And, LCM = (HCF + 57)
= 60
And, Product = LCM * HCF
= 60*3
= 180 Ans.
Therefore, LCM = (x+57)
Sum of squares = x (to the power 2) + [(x+57)(to the power 2)
ATP, sum of squares = 3609
So, x(2) + [(x+57)(square)] = 3609
X(2)+x(2)=3609-3749
2x(square)=360
2x=(under root) 360
2x = 2*2*2*3*3*5
2x = 2*3
2x = 6
X = 6/2
X = 3.
Therefore, HCF = 3
And, LCM = (HCF + 57)
= 60
And, Product = LCM * HCF
= 60*3
= 180 Ans.
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