How to solve this question
6+x-4x^2+x^3
Answers
Answered by
0
ans:x^3-4x^2+x+6
=x^3-x^2-3x^2+3x-2x+6
=x^2(x-1)-3x(x-1)-2(x-3)
=(x-1)(x^2-3x)-2(x-3)
=(x-1)(x-3)(x)-2(x-3)
=(x-3)(x(x-1)-2)
=(x-3)(x^2-x-2)
Similar questions