how to solve this question no. 26 is this question wrong or right. If right the solution
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It's correct question
since triangle ACP and ACD are on the same base and between same parallel AC and DP
ar(ACP)=ar(ACD)
Adding ar(ABC) on both sides,
ar(ACP)+ar(ABC)=ar(ACD)+ar(ABC)
ar(ABP)=ar(quadrilateral ABCD).
since triangle ACP and ACD are on the same base and between same parallel AC and DP
ar(ACP)=ar(ACD)
Adding ar(ABC) on both sides,
ar(ACP)+ar(ABC)=ar(ACD)+ar(ABC)
ar(ABP)=ar(quadrilateral ABCD).
gamer2o:
ok
NCHS
your answer is wrong
how
we have to prove tri. APD u proved ABP
oh sorry
wait
ok
got the answer
???
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