how to solve this sum
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it is very simple angle pqs=angleprs isosceles angle
psq=psr
PS = ps common
psq=psr
PS = ps common
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in triangle pqs and prs
angle psq= angle prs(90°)
pq=pr(given)
ps=par(common)
since by R.H.S both triangle are congruent
angle psq= angle prs(90°)
pq=pr(given)
ps=par(common)
since by R.H.S both triangle are congruent
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