How to solve this type of indices?? Pls answer my question...
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Answered by
1
you must give the square separately to both sides.
[Note:sqr means square]
e.g.
sqr(2/3)
=sqr(2)/sqr(3)
=4/9
Do same to the 2nd one. cube(3/5)=cube(3)/cube(5)=27/125
Now in the 3rd one....
it is sqr(2 1/2)
multiply denominator with the integer . Here you have to do is to multiply the both 2 and then add 1 in it so, (2*2)+1=5
and then put the same denominator with the number you've got, here the answer is..
sqr(5/2)=25/4
DO the same in the others and ask me if necessary. ^_^
[Note:sqr means square]
e.g.
sqr(2/3)
=sqr(2)/sqr(3)
=4/9
Do same to the 2nd one. cube(3/5)=cube(3)/cube(5)=27/125
Now in the 3rd one....
it is sqr(2 1/2)
multiply denominator with the integer . Here you have to do is to multiply the both 2 and then add 1 in it so, (2*2)+1=5
and then put the same denominator with the number you've got, here the answer is..
sqr(5/2)=25/4
DO the same in the others and ask me if necessary. ^_^
Answered by
1
1.4/9
2.27/125
3.25/4
4.1331/27
2.27/125
3.25/4
4.1331/27
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