Question

How to solve this with steps pls .one mark question

Answer 1

since sin(90-x) = cosx,
2 cos ¢ x cos ¢ = 1
cos ^2 ¢ = 1/2
cos ¢ = 1/root2
¢ = 45

Answer 2

$2 \sin(90 - \alpha ) \cos\alpha = 1 \\ 2 \cos^{2} \alpha = 1 \: \: \: \: \: \: (because.. \sin(90 - \alpha ) = \cos \alpha ) \\ \cos^{2} \alpha = \frac{1}{2} \\ \cos \alpha = + \frac{1}{ \sqrt{2} } \: \: or \: \: - \frac{1}{ \sqrt{2} } \\ \alpha = \frac{\pi}{4} \: \: or \: \: \alpha = \frac{3\pi}{4}$
hope this helps.....
if correct....
please please mark as brainlist plzz