how to solve- x^2=(8)^2+(16-x)^2
Answers
Answered by
1
x^2 = 8^2 + (16-x)^2
0 = -x^2 + 64 + 256 - 32x + x^2
0 = 320 - 32x
-320 = -32x
-320/-32 = x
10 = x
Therefore the value of x is 10
0 = -x^2 + 64 + 256 - 32x + x^2
0 = 320 - 32x
-320 = -32x
-320/-32 = x
10 = x
Therefore the value of x is 10
Sathyapriya1:
Is this right
Similar questions
English,
7 months ago
English,
7 months ago
Math,
1 year ago
Political Science,
1 year ago
Science,
1 year ago