how to solve x^2+px+q=0
Answers
Answered by
0
Hi ,
x² + px + q = 0
x² + px = - q
x² + 2 × x × p/2 = - q
x² + 2× x × p/2 + ( p/2)² = ( p/2 )² - q
( x + p/2 )² = p²/4 - q
( x + p/2 )² = ( p² - 4q )/4
( x + p/2 ) = ± √ [ ( p² - 4q )/4 ]
x = -p/2 ± √( p² - 4q )/2
x = [ ( -p ± √(p² - 4q ) ]/2
I hope this helps you.
: )
x² + px + q = 0
x² + px = - q
x² + 2 × x × p/2 = - q
x² + 2× x × p/2 + ( p/2)² = ( p/2 )² - q
( x + p/2 )² = p²/4 - q
( x + p/2 )² = ( p² - 4q )/4
( x + p/2 ) = ± √ [ ( p² - 4q )/4 ]
x = -p/2 ± √( p² - 4q )/2
x = [ ( -p ± √(p² - 4q ) ]/2
I hope this helps you.
: )
Similar questions