Question

how to solve (x2-y2) (a2-b2) +4abxy

Answer 1

(x²-y²)(a²-b²)+4abxy

= (ax)²-(ay)²- (bx)²+(by)²+4abxy

= (ax)²+(by)²+2abxy-{ (ay)²+ (bx)²-2aybx

= (ax+by)²- (ay-bx)² --------> a²- b²

= (ax+ by + ay + bx) (ax+ by- ay +bx )

= [ a(x+y) - b(x-y) ] [a (x -y)+ b(x + y )]

HOPE MY ANSWER IS USEFUL TO YOU
PLEASE MARK BRAINLIEST

Answer 2

$( {x }^{2} - {y}^{2} )( {a}^{2} - {b}^{2}) + 4abxy \\ = ( {x}^{2} )( {a}^{2}) + ( {x}^{2})( { - b}^{2}) + ( { - y}^{2})( {a}^{2}) + ( { - y}^{2})( { - b}^{2}) + 4abxy \\ = {a}^{2} {x}^{2} + - {b}^{2} {x}^{2} + - {a}^{2} {y}^{2} + {b}^{2} {y}^{2} + 4abxy \\ answer \\ = {a}^{2} {x}^{2} - {a}^{2} {y}^{2} + 4abxy - {b}^{2} {x}^{2} + {b}^{2} {y}^{2}$