How to solve xdy/dx +y=2logx by differential equation?
Answers
Answered by
0
Xdy/dx+y=2logx
Divide whole equation by x
dy/dx+y/x=2logx/x
IF=e^integrating of 1/x
IF=e^logx
=x
Y(IF)=Q(IF)dx+c
Yx=integrating2xlogx/xdx+c
yx=2/x+c
Divide whole equation by x
y=2/x^2+c/x
Here is your answer
Divide whole equation by x
dy/dx+y/x=2logx/x
IF=e^integrating of 1/x
IF=e^logx
=x
Y(IF)=Q(IF)dx+c
Yx=integrating2xlogx/xdx+c
yx=2/x+c
Divide whole equation by x
y=2/x^2+c/x
Here is your answer
Similar questions