HOW TO SUBTRACT SUMS LIKE 4a - 7ab +3b +12 FROM 12a - 9ab + 5b - 3
Answers
Answered by
9
Hello Dear!!!
here's your answer....
4a - 7ab +3b +12 FROM 12a - 9ab + 5b - 3
12a - 9ab + 5b - 3 - (4a - 7ab +3b +12)
12a - 9ab + 5b - 3 - 4a + 7ab - 3b -12
12a - 4a +5b - 3b -9ab +7ab -3 -12
8a + 2b -2a -15.
That's really easy...
you have to just subtract or add the coefficients of same terms.
__________________________________
hope this helps you....
here's your answer....
4a - 7ab +3b +12 FROM 12a - 9ab + 5b - 3
12a - 9ab + 5b - 3 - (4a - 7ab +3b +12)
12a - 9ab + 5b - 3 - 4a + 7ab - 3b -12
12a - 4a +5b - 3b -9ab +7ab -3 -12
8a + 2b -2a -15.
That's really easy...
you have to just subtract or add the coefficients of same terms.
__________________________________
hope this helps you....
Answered by
6
hii!!
here's ur answer...
u wanna know how to subtract sums like:-
4a - 7ab + 3b + 12 from 12a - 9ab + 5b - 3
first put both the equations in brackets.
now first we will write ( 12a - 9ab + 5b - 3 ) as it's written that we have to subtract ( 4a - 7ab +3b + 12 ) from ( 12a - 9ab + 5b - 3 )
now,
( 12a - 9ab + 5b - 3 ) - ( 4a - 7ab + 3b + 12 )
next step is to remove brackets.
= 12a - 9ab + 5b - 3 - 4a + 7ab - 3b - 12
we know that sign changes when we remove bracket and if there is - sign.
now we have to find like terms and then solve.
= 12a - 4a - 9ab + 7ab + 5b - 3b - 3 - 12
= 8a - 2ab + 2b - 15
see how simple it is.
ok, lemme give u one more example..
• subtract 4x - 5y - 2z from 8z - 6y + 2x.
as I told u before, first we have to put them in brackets.
then the equation will be like this :-
( 8z - 6y + 2x ) - ( 4x - 5y - 2z )
now bracket open..
= 8z - 6y + 2x - 4x + 5y + 2z
= 8z + 2z - 6y + 5y + 2x - 4x
= 10z - y - 2x
hope u understood how to solve sums like this.
and if any doubt, ping me :)
here's ur answer...
u wanna know how to subtract sums like:-
4a - 7ab + 3b + 12 from 12a - 9ab + 5b - 3
first put both the equations in brackets.
now first we will write ( 12a - 9ab + 5b - 3 ) as it's written that we have to subtract ( 4a - 7ab +3b + 12 ) from ( 12a - 9ab + 5b - 3 )
now,
( 12a - 9ab + 5b - 3 ) - ( 4a - 7ab + 3b + 12 )
next step is to remove brackets.
= 12a - 9ab + 5b - 3 - 4a + 7ab - 3b - 12
we know that sign changes when we remove bracket and if there is - sign.
now we have to find like terms and then solve.
= 12a - 4a - 9ab + 7ab + 5b - 3b - 3 - 12
= 8a - 2ab + 2b - 15
see how simple it is.
ok, lemme give u one more example..
• subtract 4x - 5y - 2z from 8z - 6y + 2x.
as I told u before, first we have to put them in brackets.
then the equation will be like this :-
( 8z - 6y + 2x ) - ( 4x - 5y - 2z )
now bracket open..
= 8z - 6y + 2x - 4x + 5y + 2z
= 8z + 2z - 6y + 5y + 2x - 4x
= 10z - y - 2x
hope u understood how to solve sums like this.
and if any doubt, ping me :)
Anonymous:
Awesome explaination !!
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