Math, asked by littledude, 1 year ago

how to take out the square root of any number??

Answers

Answered by Divyankasc
2
Let us try to take out the square root of 171.
Plz refer to the image.. Steps ---
Step 1: Place a bar over every pair of digits starting from the unit digit. If the number of digits in it is odd, then the left-most single digit too will have a bar.Thus we have, 171.So 1st bar is on 71 and 2nd bar is on 1.

Step 2 : Find the largest number whose square is less than or equal to the 1st number,here it is '1'.

Step 3: Bring down the number under the next bar (i.e., 71 in this case) to the right of the remainder.

Step 4 : Add the divisor 1 and quotient 1 that gives us 2.

Step 5 : Think of a largest number in fill in the blank in such a way that the product of a new divisor and this digit is equal to or less than 71(new dividend). In this case 23 ×3 = 69.

Step 6 : Continue the same pattern (Add zeros as required)

littledude: bar??
littledude: i didnt understand at all
littledude: which quotient which remainder
Divyankasc: Umm sorry I forgot to add the image
Divyankasc: Sorrryy...Now the edit option is not available!  
Divyankasc: Go to  http://brainly.in/question/223896
Divyankasc: U will understand! 
Answered by vempatapupadmaja31
0

Step-by-step explanation:

we have two chances that the number is perfect square we can take out the roots easily

for example:

i have to take _/ 25 is my value so i have to change this in normal number that is real number

we know that 25 is a perfect a

square of 5

so we have to write as _/(5)^2

here square and root will be cancelled out

so answer will be 5

2nd method is long division method

for long division method i have to attach the picture so refer that.

Attachments:
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