How to tie 90 cows in 9 wood in odd order
Answers
Step-by-step explanation:
I assume that no cow may be tied to more than one pole, although that was not stated. The number of cows at each pole must be an integer, and since they cannot be even, they must all be odd.
Any odd number can be written in the form 2n + 1, where n is an integer. Suppose that there is a solution. Let these be the nine numbers:
(2a + 1), (2b + 1), ... , (2i + 1)
where a, b, c, d, e, f, g, h, and i are integers.
sum = 2(a + b + c + d + e + f + g + h + i) + 9
2(a + b + c + d + e + f + g + h + i) + 9 = 90
2(a + b + c + d + e + f + g + h + i + 4) + 1 = 90
Therefore, 90 is an odd number. Clearly this is not true. The contradiction disproves the hypothesis. There is no set of nine odd numbers whose sum is 90.
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