How to write reduction and oxidation half reaction...plx... explain kar k dou with example...i will mark that person as brainliest....plzz ... urgent hai....
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You can write a redox reaction as two half-reactions, one showing the reduction process, and one showing the oxidation process. Fe3+ is gaining an electron to become Fe2+. Iron is therefore being reduced and tin is the reducing agent (causing iron to be reduced). The reduction half-reaction is:
Fe3+(aq) + e−→Fe2+(aq)
Sn2+ is losing two electrons to become Sn4+. Tin is therefore being oxidised and iron is the oxidising agent (causing tin to be oxidised). The oxidation half-reaction is:
Sn2+(aq)→Sn4+(aq) + 2e−
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