Question

How to write standard form of equation through point (-6,-2) and Slope - 1/3?

Answer 1

(y - y')= m(x-x') is the std eqn

where,

x',y' are given points and m= slope

so above points can written as,

y-(-2)=(-1/3)(x-(-6 )

(y+2)(-3)=x+6

-3y-6=x+6

x+3y+12=0. is required std. eqn