Question

how to write tanA in terms of sinA?

Answer 1

hii!
tanA=sinA/cosA

= sinA /_/1- sin^2 A
hope this may help u ..
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Answer 2

tan A = sin A/cos A

We know that, sin²A + cos²A = 1

» cos²A = 1-sin²A

» cosA = √(1-sin²A)

tan A = sin A/√(1-sin²A)

Hope it helps