Question

If 200 calories heat energy is required 40 grams of liquid to its gaseous state then the latent of vapourization of it is

Answer 1

Latent heat of vaporisation is the heat required to convert liquid into gas without raising its temperature.

Then latent heat of vaporisation is 200/40 calorie per gram

=> 5 cal/g

1 calorie = 4.184 Joules

Therefore 5 calorie = 4.184 × 5
= 20.92 Joules

Therefore latent heat of vaporisation is
= 20.92 J/g

Answer 2

heat required to convert 40 grams of liquid which gaseous state is 200 calories

so heat required to convert 1 gram of the liquid to its gaseous state is 50 J

latent heat of vaporization of that liquid is 50 joules per gram