Question

how W = QV in electricity​

Answer 1

Explanation:

The electric power in watts produced by an electric current I consisting of a charge of Q coulombs every t seconds passing through an electric potential (voltage) difference of V is P=QVt=IV P = QV t = IV , where Q is electric charge in coulombs, t is time in seconds, I is electric current in amperes, and V is electric ...

Answer 2

Answer:

First of all, let's analyse what Charge (Q) and Voltage (V) means here.

Q - Charge is the number of electrons (they possess the charge) there. For an extra knowledge I'm telling you that, 1 coulomb charge is got from a number of 6.24×10¹⁸ electrons (approx.)

V - Voltage (also called potential difference) is the work done (W) to move a charge of 1 C from one point to another.

Remember that, here 'work done' means the energy utilised to do a work (eg: energy utilised to light a bulb, work an electric pump, electric generator)

So, we said that Voltage is the Work done to a move a charge of 1 C or we can say, Work done per coulomb of charge.

Writing this as an equation, we get

$Voltage= \frac{Work done}{Charge} \ \\ \ V= \frac{W}{Q}$

Using simple maths, we can simply get the equation to calculate W. We get,

Work = Charge × Voltage

Work = Charge × VoltageW = QV (this is the answer to your question)

Then, how can we define work?

Work done is the total energy utilised to move the given number of charges.

Furthermore, we can get the equation to find out Charge from these equations. We get,

$Charge= \frac{Work done}{Voltage} \\ \\ Q = \frac{W}{V}$

So, we got here three equations,

1. V = W/Q
2. Q = W/V
3. W = QV

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