How we can know that a number have a rational square root
assthha161:
For example the number is √156.25
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by using for b^=√4ac
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hey mate
Very-well-known proof by contradiction: if √n were rational, let √n = a/b, with a,b in lowest reduced form, hence have no common divisor. ... You can also take the square root of a rational non-integer, that is a fraction, and if the numerator and denominator are both perfect squares, you will have rational square roots.
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