how we easily understand triangles sum
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because all know triangle have three sides
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(A)By construction:-
1) Draw a triangle on a sheet of paper. Any sort of triangle you like. Use the ruler or straight-edge to ensure the sides are straight:
2) Colour the edges of the triangles. Do not colour the inside of the triangle. If you really want to colour the inside of the triangle, then use a different colour for the inside from the edges:
3) Cut out the triangle. Make sure the edges are as straight as possible:
4) Cut the corners off the triangle. Make the corners large enough so they are easy to handle:
Notice that each corner has two coloured edges and one uncoloured edge. (I should have used a more contrasting colour than green – maybe red – or else pressed harder when I coloured.
5) Draw a straight line on a sheet of paper using the ruler (I used one of the scraps from the paper I cut the triangle out of):
6)Assemble the corners on the straight line. Ensure that (1)coloured edges touch the straight line and (2) coloured edges touch other coloured edges.
(B)By proving:-
Proof:Consider a ∆ABC, as shown in the figure below.To prove the above property of triangles, draw a line
←→
P
Q
parallel to the side BC of the given triangle.
Since PQ is a straight line, it can be concluded that:
∠PAB + ∠BAC + ∠QAC = 180° ………(1)
SincePQ||BCand AB, AC are the transversals,
Therefore, ∠QAC = ∠ACB (pair of alternate angles)
Also, ∠PAB = ∠CBA(pair of alternate angles)
Substituting the value of ∠QAC and∠PAB in equation (1),
∠ACB + ∠BAC + ∠CBA= 180°
Thus, the sum of interior angles of a triangle is 180°.
1) Draw a triangle on a sheet of paper. Any sort of triangle you like. Use the ruler or straight-edge to ensure the sides are straight:
2) Colour the edges of the triangles. Do not colour the inside of the triangle. If you really want to colour the inside of the triangle, then use a different colour for the inside from the edges:
3) Cut out the triangle. Make sure the edges are as straight as possible:
4) Cut the corners off the triangle. Make the corners large enough so they are easy to handle:
Notice that each corner has two coloured edges and one uncoloured edge. (I should have used a more contrasting colour than green – maybe red – or else pressed harder when I coloured.
5) Draw a straight line on a sheet of paper using the ruler (I used one of the scraps from the paper I cut the triangle out of):
6)Assemble the corners on the straight line. Ensure that (1)coloured edges touch the straight line and (2) coloured edges touch other coloured edges.
(B)By proving:-
Proof:Consider a ∆ABC, as shown in the figure below.To prove the above property of triangles, draw a line
←→
P
Q
parallel to the side BC of the given triangle.
Since PQ is a straight line, it can be concluded that:
∠PAB + ∠BAC + ∠QAC = 180° ………(1)
SincePQ||BCand AB, AC are the transversals,
Therefore, ∠QAC = ∠ACB (pair of alternate angles)
Also, ∠PAB = ∠CBA(pair of alternate angles)
Substituting the value of ∠QAC and∠PAB in equation (1),
∠ACB + ∠BAC + ∠CBA= 180°
Thus, the sum of interior angles of a triangle is 180°.
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