Question

How we find the kinetic energy of the emitted alpha-particle in alpha-decay

Answer 1

momentum is zero before and after the disintegration. => mDVD=mαVαmDVD=mαVα
So , net energy
1/2mDV2d+1/2mαV2α=8.95412MeV
1/2mDVd2+1/2mαVα2=8.95412MeV
1/2mdV2d=1/2Vd(mαVα)=1/2mαVαmd×(mαVα)=mαmd×KEα
1/2mdVd2=1/2Vd(mαVα)=1/2mαVαmd×(mαVα)=mαmd×KEα
so,
(1+mαmd)×KEα=8.95412MeV
(1+mαmd)×KEα=8.95412MeV
Now solve this to get the KE of αα particle