the inner diameter of a cylindrical wooden pipe is 24cm and its outer diameter is 28cm .the pipe is 35cm long .find the mass of the pipe if 1cmcube of wood has a mass of 0.6gm
Answers
Answer:
3.432 kg
Step-by-step explanation:
Find the radius:
r1 = 28 ÷ 2 = 14 cm
r2 = 24 ÷ 2 = 12 cm
Find the volume of the wood:
Volume = πh(r1² - r2²)
Volume = π(35)(14² - 12²)
Volume = 5720 cm³
Find the mass of the pipe:
1 cm³ = 0.6g
5720 cm³ = 0.6 x 5720 = 3432g or 3.432 kg
Answer: The mass is 3.432kg
Answer: 3.432 kg
Step-by-step explanation: to find mass
we have to find volume of pipe
Volume of pipe = volume of outer cylinder - volume of inner cylinder
Outer cylinder
Radius of outer cylinder, r₁ = D/2
28 / 2
= 14 cm
height = 35 cm
Volume of outer cylinder = πr₁²h
= π (14)² 35
Inner cylinder
Radius of inner cylinder r₂ = D / 2
= 24 /2
= 12 cm
height = 35 cm
Volume of inner cylinder= πr₂²h
=π (12)²35
So, the volume of pipe = volume of outer cylinder - volume inner cylinder
=π (35) (14² - 12²)
=22/7 × 35 ( 196 - 144)
= 5720 cm³
Mass of 1 cm is 0.6 gm
∴ mass of 5720 cm = 5720 × 0.6 gm
= 5720 × 0.6 /1000 kg
= 3.432 kg