Question

how will the magnetic field produced in a current carrying circular coil if we increase (a) the amount of current (b) distance from the coil​

Answer 1

Explanation:

$\rm{Displacement, x = at^{2} - bt^{3}}$

$\rm{Velocity ,v = \dfrac{dx}{dt}}$

$\rm{\dfrac{d}{dt}(at^2- bt^3)}$

$\rm{ v = 2at - 3bt^2}$

$\rm{Acceleration,A = \dfrac{dv}{dt} = \dfrac{d}{dt}(2at - 3bt^2)}$

$\implies\rm{ 2a -(3)(2)bt}$

$\implies\rm{A = 2a - 6bt}$

$\rm{ At\:time,\:t = 2sec}$

$\rm{Acceleration\:,A = 2a- 6b(2)}$

$\rm{ 2a - 12b}$

$\rm{ 2(a-6b)}$