Question

how will the weight of a body of mass 100g change if it is taken from equator to the poles ? give reason for your answer

Answer 1

g is acceleration due to gravity.
g is inversely proportional to radius. as radius increases value of g decreases. so it is least at equator and maximum at poles.

$g = \frac{m1m2}{ {r}^{2} }$
mass of Earth is roughly 5.972×10^27g. and mass of object is 100g.
radius of Earth at equator= 6.378×10^6 m
radius of Earth at poles= 6.356×10^6 m

g (at equator) = (5.972×10^27 × 100) / 6.378 × 10^6
= 93.6 × 10^21 m/s²

g (at poles) = (5.972×10^27 × 100) / 6.356 × 10^6
= 93.9 × 10^21 m/s²

now as weight = mass × g

weight at equator will be 9360g or 9.360kg

weight at poles will be 9390g or 9.390kg

note: 10^21 has been taken common in both. hence neglected for ease of understanding.


I hope this is clear to you.
best of luck.