How will you calculate how many moles of glucose present in 320 mL of 5.0 M of glucose solution?
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Answered by
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mass of C = 12u mass of H = 1u mass of O = 16u
amu of sugar =( 12*12) + (1*22)+ (16*11)
=144 + 22 + 176 = 342u
molar mass = 342 gram
mass = no. of moles * molar mass = 0.5 * 342 = 171 gram
PLEASE MARK MY ANSWER AS A BRAINLIEST.
amu of sugar =( 12*12) + (1*22)+ (16*11)
=144 + 22 + 176 = 342u
molar mass = 342 gram
mass = no. of moles * molar mass = 0.5 * 342 = 171 gram
PLEASE MARK MY ANSWER AS A BRAINLIEST.
Answered by
0
171 gram above answer is right
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