Question

how will you connect 3 resistor each of 6 ohm to get total resistance of (i) 9 ohm and 4 ohm?​

Answer 1

Answer:

Explanation:

Given that,

R1=R2=R3=6 Ohm

When all are connected in series then equivalent resistance is given by,

(R)eq=R1+R2+R3=(6+6+6)=18 Ohm

When two of them (say R1 and R2)are connected in parallel, their equivalent is given by Req={(R1×R2)/(R1+R2)}=(6×6)/6+6=36/12=3 Ohm

When this equivalent is connected in series with the third , their equivalent becomes,

3 Ohm +6 Ohm=9 Ohm.

When all of the three are connected in parallel,then

(R)eq=(R1×R2×R3)/(R1+R2+R3)

=6×6×6/(6+6+6)=36×6/18=12 Ohm

When two are in series and their equivalent in parallel with the third then,

(6+6) parallel 6

=12×6/(12+6)=72/18=4 Ohm

Answer 2

Referred to the attachments.......