how will you convert aniline into phenol and p-amino azobenzene?
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Answered by
51
I think you will undestand from this....
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gulshan25:
thanks
Answered by
16
Hey dear,
● Aniline to phenol -
Aniline is first treated with HCl/NaNO2 to form benzene diazonium chloride.
C6H5-NH2 + HCl --> C6H5-N2Cl
Benzene diazoium chloride on warming with water yields phenol.
C6H5-N2Cl + H2O --> C6H5-OH + N2 + HCl
● Aniline to p-aminoazobenzene -
Aniline is first treated with HCl/NaNO2 to form benzene diazonium chloride.
C6H5-NH2 + HCl --> C6H5-N2Cl
Benzyl diazonium chloride again reacts with aniline ti form p-aminoazobenzene.
C6H5-N2Cl + C6H5-NH2 --> C6H5-NH-C6H5 + N2 + HCl
Hope this cleared your doubts ...
● Aniline to phenol -
Aniline is first treated with HCl/NaNO2 to form benzene diazonium chloride.
C6H5-NH2 + HCl --> C6H5-N2Cl
Benzene diazoium chloride on warming with water yields phenol.
C6H5-N2Cl + H2O --> C6H5-OH + N2 + HCl
● Aniline to p-aminoazobenzene -
Aniline is first treated with HCl/NaNO2 to form benzene diazonium chloride.
C6H5-NH2 + HCl --> C6H5-N2Cl
Benzyl diazonium chloride again reacts with aniline ti form p-aminoazobenzene.
C6H5-N2Cl + C6H5-NH2 --> C6H5-NH-C6H5 + N2 + HCl
Hope this cleared your doubts ...
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