Question

how will you find the area of a rectangle with the length of x+7/x²-25 and a width of x²+10x+25/x²-49​

Answer 1

Answer:

(x+7/x^2-25)(x^2+10x+25/x^2-49)

x^2-25=(x+5)(x-5)

x^2-49=(x+7)(x-7)

x^2+10x+25=x^2+5x+5x+25=(x+5)^2

[x+7/(x+5)(x-5)][(x+5)(x+5)/(x+7)(x-7)]

so x+7 gets cancelled and x+5 gets cancelled

(1/x-5)(x+5/x-7)

=x+5/(x-5)(x-7)

=x+5/x^2-12x+35

Answer 2

Answer:

Step-by-step explanation: