how will you find the area of a rectangle with the length of x+7/x²-25 and a width of x²+10x+25/x²-49
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(x+7/x^2-25)(x^2+10x+25/x^2-49)
x^2-25=(x+5)(x-5)
x^2-49=(x+7)(x-7)
x^2+10x+25=x^2+5x+5x+25=(x+5)^2
[x+7/(x+5)(x-5)][(x+5)(x+5)/(x+7)(x-7)]
so x+7 gets cancelled and x+5 gets cancelled
(1/x-5)(x+5/x-7)
=x+5/(x-5)(x-7)
=x+5/x^2-12x+35
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