Question

How work is done in moving a charge of 78 C across two points having potential differnce 14 V

Answer 1

Given

➲ Charge flowing = 78 C

➲ Potential difference = 14 V

To find

➲ Work done in moving that charge

Solution

Here we have as follows ;

⇒ Charge (Q) = 78 C

⇒ Potential difference (V) = 14 v

Now as we know that, potential difference is division of work done and charge flowing.

⇒ V = W/Q

Substituting values,

⇒ 14 = W/78

⇒ W = 14 × 78

⇒ W = 1092 J

Converting it into Kilojoules :

⇒ W = (1092/1000) kJ

⇒ W = 1.092 kJ

∴ Work done in moving that charge = 1092 J or 1.092 kJ [Answer]

__________________________

Some more formulas related :

➲ Ohm's law : V = I * R

Here,

• V denotes potential difference
• I denotes current
• R denotes resistance

➲ I = Q/t

Here,

• I denotes electric current
• Q denotes Charge
• t denotes time

➲ P = W/t

Here,

• P denotes power
• W denotes work done
• t denotes time

➲ Energy consumed = V²/Rt

➲ P.E. = m * g * h

Here,

• P.E. denotes potential energy
• m denotes mass
• g denotes gravitational acceleration
• h denotes height

➲ K.E. = ½ * mv²

Here,

• K.E. denotes kinetic energy
• m denotes mass
• v denotes velocity

Answer 2

Given ,

Charge (q) = 78 C

Potential difference (v) = 14 v

We know that ,

$\boxed{ \sf{Potential \: difference \: (v) = \frac{work \: done}{charge}} }$

Thus ,

14 = Work/78

Work = 14 × 78

Work = 1092 J

$\therefore \sf \underline{The \: work \: done \: is \: 1092 \: J}$