Question

How would pressure change of area is halved keeping force constant.

Answer 1

Explanation:

Let us say, The Force = F

Pressure = P

Area = A

we know,

Pressure = Force / Area

P(1) = F(1)/A(1).....(I)

Now the force is constant and Area is doubled

A(2) = 2A(1) &. F(1) = F(2)

therefore,

P(2) = F(2) / A(2).......(II)

dividing equation (I) by (II)

$\frac{p(1)}{p(2)} = \frac{ \frac{f1}{a1} }{ \frac{f2}{a2} }$

therefore we know

A(2) = 2A(1) &. F(1) = F(2)

Then,

P1 / P2 = A(2) / A(1)

P1 / P2 = 2A(1) / A(1).....[A(2) = 2A(1)]

Therefore,

P1 = 2P2

Thus if Area is halved the pressure is doubled by factor of 2

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