How would the period of a simple pendulum be affected if it were located on the moon instead of the earth?
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The time period of the simple pendulum is 2π√ (l/g). The time period is adversely proportional to the acceleration due to gravity.
Time period could increase by √6 when compared to the earth.
Hence, pendulum would swing slower and the frequency will also be on the lower side.
Time period could increase by √6 when compared to the earth.
Hence, pendulum would swing slower and the frequency will also be on the lower side.
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