How would u join three resistors of 9ohms to get a total effective resistance of 6 ohms?
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2 resistors in series and 1 in parallel.
R' = R1+R2
R' = 9+9 = 18
Now, R'R3/ R'+R3
18 × 9 / 18 + 9
162 / 27 = 6ohm
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