how would you justify the presence of IB elements in the 5th period of periodic table.
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The order in which the enery of the available orbitals 4d,5s and 5p increases in 5s<4d<5p. The total number of orbitals available is 9. The maximum number of electrons that can be accommodated is 18, and therefore 18 elements are there in the 5th period
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