Question

How would you prepare 72.5 g of an aqueous solution that is 5.00% potassium iodide, KI, by mass?

Answer 1

Answer:

By mixing 3.625 g of KI in 68.875 g of solvent we can prepare the 72.5 g of 5% KI aqueous solution.

Explanation:

Mass of the solution = 72.5 g

Mass of the solute that potassium iodide = x

Given that aqueous solution is 5.00% potassium iodide by mass.

$\%=\frac{\text{Mass of solute}}{\text{Mass of solution}}\times 100$

$5\%=\frac{x}{72.5 g}\times 100$

x =3.625 g

Mass of solvent = 72.5 g = 3.625 g = 68.875 g

By mixing 3.625 g of KI in 68.875 g of solvent we can prepare the 72.5 g of 5% KI aqueous solution.