Question

hu anglian Kalam pack​

Answer 1

Answer:

$y = sinx \\ \\ \frac{dy}{dx} = cosx \\ \\ \frac{ {d}^{2} y}{d {x}^{2} } = - sinx = - y\\ \\ \frac{ {d}^{2} y}{d {x}^{2} } + y = 0$