Question

hudrogen and oxygen combine in the ratio of 1: 8 by mass to form water. What
mass of oxygen gas would be required to react completely with 3 g of hydrogen
gas?
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Answer 1

Answer:

sorry sis I don't know this

Answer 2

Answer:

The law of constant proportions states that in a chemical substance, the elements are always present in definite proportions by mass. Hydrogen and oxygen combine in the ratio of 1:8 by mass to form water.

1g of hydrogen reacts with oxygen = 8g

Thus, in order to form water, 3 x 8 = 24 g of oxygen will react completely with 3 g of hydrogen gas.

Concept insight: Recall the law of constant proportions and then apply that in a chemical substance, the elements are always present in definite proportions by mass.

I can also provide uh the calculation :

2H2+O2→2H2O

 4g        32g       36g

Since, 32 g of oxygen reacts with 4g of H2.

So, 3g of H2 will require =

$\frac{3 \times 32}{4} = 24$

 grams of O2