huma,hubna and seema received a total of rs 2016 as monthly allowance from their mother such that seema gets 1/2 of what huma gets and hubna gets 1 2/3 times seemas share.how much money do the three sisters get individually?
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Answered by
216
Let the share of huma be 'x'
Then,the share of seema by the problem will be x/2
And the share of hubna will be 1 2/3*x/2=5x/6
Total money is Rs.2016
⇒x+x/2+5x/6=Rs.2016
⇒(6x+3x+5x)/6=Rs.2016
⇒14x/6=Rs.2016
⇒x=2016*6/14
⇒x=864.
Therefore,huma's share = x= Rs.864
Seema's share = x/2 = Rs.432
And Hubna's share = 5x/6= Rs.720 .
Then,the share of seema by the problem will be x/2
And the share of hubna will be 1 2/3*x/2=5x/6
Total money is Rs.2016
⇒x+x/2+5x/6=Rs.2016
⇒(6x+3x+5x)/6=Rs.2016
⇒14x/6=Rs.2016
⇒x=2016*6/14
⇒x=864.
Therefore,huma's share = x= Rs.864
Seema's share = x/2 = Rs.432
And Hubna's share = 5x/6= Rs.720 .
Answered by
40
Answer:
Therefore,huma's share = x= Rs.864
Seema's share = x/2 = Rs.432
And Hubna's share = 5x/6= Rs.720
Step-by-step explanation:
Let the share of huma be 'x'
Then,the share of seema by the problem will be x/2
And the share of hubna will be 1 2/3*x/2=5x/6
Total money is Rs.2016
⇒x+x/2+5x/6=Rs.2016
⇒(6x+3x+5x)/6=Rs.2016
⇒14x/6=Rs.2016
⇒x=2016*6/14
⇒x=864.
Therefore,huma's share = x= Rs.864
Seema's share = x/2 = Rs.432
And Hubna's share = 5x/6= Rs.720
BY GIRI OF 7A
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