Question

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Fast solve this maths question !!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Answer 1

⭐HEY GUYS HERE IS ur answer⭐

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✔✔If x + y + z = 0 , Prove that x³ + y³ + z³ = 3xyz

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✔✔Solution ....

x + y + z = 0

x + y = -z..........(i)


(x + y)³ = (-z)³ (cubing both side)

x³ + y³ + 3xy(x + y) = (-z)³

✰Using formula (a + b)³ = a³ + b³ + 3ab(a + b)

x³ + y³ + 3xy( - z ) = (-z)³ ................(from i putting the value of x + y = -z )


x³ + y³ - 3xyz = (-z)³

x³ + y³ + z³ = 3xyz ....proved ...


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I HOPE IT WILL HELP YOU☺️✌️

Thank you✌️

Answer 2

$\color{red}{ \bf{hey}}$


$\color{green}{ \bf \underline{here \: is \: the \: answer}}$


$\color{green}{ \bf \underline{here \: is \: the \: answer}}$
⬇⤵⬇⤵✌

⬇⤵⬇⤵❕✌

x+y+z=0

⏩x+y=-z .....(1)

⏩x³+y³+z³=3xyz

LHS..
x³+y³=-z³

put formula (a³+b³)

x³+y³+3xy(x+y)=-z³

x³+y³+3xy(-z).......(from 1)

x³+y³-3xyz=-z³

x³+y³+z³=3xyz


$\color{blue}{ \underline{proved}}$

$\color{red}{ \bf{ hope \: it \: helps}}$

✌✌✌✌✌⭐⭐⭐⭐

$\boxed{thanks}$