Question

No 7 please can anyone help with detailed answe

Answer 1

Explanation:

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Answer 2

From t0 to t1

Displacement-1/2 x 1 x 10=5m(area of triangle)

from t1 to t4

displacement-4 x 10=40m(area of rectangle)

from t4 to t5

displacement- 1/2(10+20) x 1= 15m(area of trapezium)

from t5 to t6

displacemen- 1/2 x 1 x 20=10m(area of triangle)

Therefore, total displacement=5+40+15+10=70m

Therefore,avg velocity=total displacement/total time

70/6=11.666 m/s

Instantaneous velocity at t3=10 m/s

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