Hurry!! kx²-2kx+6=0 plz solve it as fast as you can...
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Given equation: kx2-2kx+6=0
the basic form of any quadratic equation is:
ax2+bx+c=0.
So: a=k, b=-2k, c=6.
for any equation having equal roots,
b2-4ac=0, or b2=4ac;
So (-2k)2=4*k*6
4k2=24k
4k*k=24*k
eliminating k;
4k=24
k=6 ans.
@skb
the basic form of any quadratic equation is:
ax2+bx+c=0.
So: a=k, b=-2k, c=6.
for any equation having equal roots,
b2-4ac=0, or b2=4ac;
So (-2k)2=4*k*6
4k2=24k
4k*k=24*k
eliminating k;
4k=24
k=6 ans.
@skb
kartik338:
Whats means by eliminating k?
K is present on lhs as well as rhs...eliminating k refers to cutting k☺
its k² on lhs how it eliminate
K squ on lhs and k on rhs....cut k of rhs with squ of lhs
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