Question

hv = hvo + 1/2mv^2
meaning of hv and hvo​

Answer 1

This expression is given by concept of  photoelectric effect.

according to photoelectric effect, when light is incident on a metal surface, some amount required to release photons from its surface and rest is used to increase the kinetic energy of ejected photons.

if we assume energy of incident light is E

then, expression will be $E=E_0+K.E$

now, energy of one photon is the product of plank's constant and its frequency.

so, E = hv and $E_0=hv_0$

and you know Kinetic energy = 1/2 mv²

so, expression converts into $h\nu=h\nu_0+\frac{1}{2}mv^2$

now I think, you got it.

hv is the energy of incident light or photon.

hv0 is the energy of ejected photon from metal surface.

Answer 2

This expression is given by concept of photoelectric effect.

according to photoelectric effect, when light is incident on a metal surface, some amount required to release photons from its surface and rest is used to increase the kinetic energy of ejected photons.

if we assume energy of incident light is E

then, expression will be E=E_0+K.E

now, energy of one photon is the product of plank's constant and its frequency.

so, E = hv and E_0=hv_0

and you know Kinetic energy = 1/2 mv²

so, expression converts into h\nu=h\nu_0+\frac{1}{2}mv^2

now I think, you got it.

hv is the energy of incident light or photon.

hv0 is the energy of ejected photon from metal surface.