Chemistry, asked by trisha10433, 1 year ago

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Answered by Anonymous
2

Hee    Your answer   Here ,Mass before absorption of water =4gm After absorption=7gm Water absorbed by it is= 7-4/4*100 =3/4*100 =75%   Thanks   Jay hind    


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Answered by siddhartharao77
6

Given,

Mass of dry rasins = 4 gm.

Mass of rasins after soaking = 7 gm.

So, mass of water absorbed = 7 - 4 = 3 gm.

Now,

% of water absorbed by rasin = (Mass of water absorbed)/Mass of dry rasin

= > 25 * 3

= > 75%.


Hope it helps!

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