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Hee Your answer Here ,Mass before absorption of water =4gm After absorption=7gm Water absorbed by it is= 7-4/4*100 =3/4*100 =75% Thanks Jay hind
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Given,
Mass of dry rasins = 4 gm.
Mass of rasins after soaking = 7 gm.
So, mass of water absorbed = 7 - 4 = 3 gm.
Now,
% of water absorbed by rasin = (Mass of water absorbed)/Mass of dry rasin
= > 25 * 3
= > 75%.
Hope it helps!
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