Math, asked by Anonymous, 11 months ago

hy guys



Prove that the circles described on the four sides of a rhombus as diameters, pass through the point of intersection of its diagonals.

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Answers

Answered by shivamchavan2003843
11

Answer:

Joh aapka hukoom sarkar....!!!

Let ABCD be a rhombus whose diagonals AC and BD intersect at O. We know that, diagonals of a rhombus intersect each other at right angle. Thus, the circles described on the four sides of a rhombus as their respective diameters, pass through the point of intersection of its diagonals. Hence, proved.

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Answered by ItzSmartyYashi
36

\huge{\underline{\mathbb{\blue{SOLUTION}}}}

\color{red}\huge\bold\star\underline\mathcal{Let}\star

ABCD be a rhombus AC and BD intersect at O.

We know that diagonals of a rhombus intersect each other at right angle.

∠AOB = ∠BOC = ∠COD = ∠AOD = 90°

\color{red}\huge\bold\star\underline\mathcal{Since,}\star

Circles with AB, BC ,CD and DA as their respective diameters pass through O.

\color{red}\huge\bold\star\underline\mathcal{Thus,}\star

Circles described on the four sides of Enormous as their respective diameters pass to the point of intersection of its diagonals.

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\huge{\underline{\mathbb{\pink{Thankyou}}}}

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