Question

hy plz solve this plz plz plz plz fast

Answer 1

we take theta = x
tan x = sin X/√1-sin X
take r.h.s. and l.h.s. = sin X/√1-sin X
squaring both sides , we get,
tan² X = sin² X / 1- sin² X
1- sin² X= cos² X
put at the place of 1-sin² X
tan² X = sin² X/ cos² X
tan x = sin X/cos X
then
tan²x = tan² X
hence proved

Answer 2

what he said is correct