Question

hy Siddhartha plzz solve

Answer 1

✴hy✴
✳here is your answer✴

solution:- x^4+4

=(x^4+4x²+4)-4x²

=(x²+2)²-(2x)²=(x²+2-2x)(x²+2+2x)

=(x²-2x+2)(x²+2x+2)

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solution:- x^4+4x²+3

=x^4+4x²+4-1

=(x^4+4x²+4)-1

=(x²+2)²-1

=(x²+2+1)(x²+2-1)

=(x²+3)(x²+1)

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I hope you understand

Answer 2

(i) x^4 + 4

It can be written as x^4 + 4 + 4x^2 - 4x^2

(x^2 + 2)^2 - (2x)^2

We know that a^2 - b^2 = (a + b)(a - b)

 (x^2 + 2x + 2)(x^2 - 2x + 2)


(ii) 

Given Equation is x^4 + 4x^2 + 3

x^4 + x^2 + 3x^2 + 3

x^2(x^2 + 1) + 3(x^2 + 1)

(x^2 + 1)(x^2 + 3).


Hope this helps!