Question

hybridisation of NH2-​

Answer 1

Answer:

H=21[V+M−C+A]

where,

H = Number of orbitals involved in hybridization.

V = Valence electrons of the central atom.

M = Number of monovalent atoms linked to the central atom.

C = Charge of the cation.

A = Charge of the anion.

NH2−

H=21[5+2+1]=4.

⇒sp3 hybridized state.