Hydrated sodium carbonate weighting 4g,contains 2.52g of water of crystallisation.The formula of hydrated salt is
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Hey buddy,
# Answer = Na2CO3.10(H2O).
# Explanation
Let's consider hydrated salt of sodium carbonate with x water of crystallization. Then molecular formula will be Na2CO3.x(H2O).
Let's assume m moles of Na2CO3, then xm moles of water.
Weight of sodium carbonate only=1.48g
Molecular mass of sodium carbonate = 2×23+12+3×16 = 106
Moles of sodium carbonate m = 1.48/106 ...(1)
Weight of water only=2.52g
Molecular mass of water = 2×1+16 = 18
Moles of water xm = 2.52/18 ...(2)
Putting (1) in (2),
x(1.48/106)=2.52/18
x = 2.52×106/1.48×18
x = 10
Thus, hydrated salt contains 10 water of crystallization.
y=1.48g
Molecular mass of sodium carbonate = 2×23+12+3×16 = 106
Moles of sodium carbonate m = 1.48/106 ...(1)
Weight of water only=2.52g
Molecular mass of water = 2×1+16 = 18
Moles of water xm = 2.52/18 ...(2)
Putting (1) in (2),
x(1.48/106)=2.52/18
x = 2.52×106/1.48×18
x = 10
Thus, hydrated salt contains 10 water of crystallization with formula Na2CO3.10(H2O).
...
# Answer = Na2CO3.10(H2O).
# Explanation
Let's consider hydrated salt of sodium carbonate with x water of crystallization. Then molecular formula will be Na2CO3.x(H2O).
Let's assume m moles of Na2CO3, then xm moles of water.
Weight of sodium carbonate only=1.48g
Molecular mass of sodium carbonate = 2×23+12+3×16 = 106
Moles of sodium carbonate m = 1.48/106 ...(1)
Weight of water only=2.52g
Molecular mass of water = 2×1+16 = 18
Moles of water xm = 2.52/18 ...(2)
Putting (1) in (2),
x(1.48/106)=2.52/18
x = 2.52×106/1.48×18
x = 10
Thus, hydrated salt contains 10 water of crystallization.
y=1.48g
Molecular mass of sodium carbonate = 2×23+12+3×16 = 106
Moles of sodium carbonate m = 1.48/106 ...(1)
Weight of water only=2.52g
Molecular mass of water = 2×1+16 = 18
Moles of water xm = 2.52/18 ...(2)
Putting (1) in (2),
x(1.48/106)=2.52/18
x = 2.52×106/1.48×18
x = 10
Thus, hydrated salt contains 10 water of crystallization with formula Na2CO3.10(H2O).
...
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Answer:
the answer is AXH2
hope it helps you
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