Question

Hydrogen and oxygen are known to form two compounds. The hydrogen content in one of them is 5.93% while in the other it is 11.2% . Show that the data illustrate the law of multiple proportion.​

Answer 1

Answer:

$\huge \: Given:$

• Hydrogen and oxygen are known to form two compounds. The hydrogen content in one of them is 5.93% while in the other it is 11.2% .

$\huge \: To Find:$

• Show that the data illustrate the law of multiple proportion.

$\huge \: Solution:$

For hydrogen peroxide, 100 g of sample will contain 5.93 g hydrogen and 100−5.93=94.07 g oxygen respectively.

The ratio of the mass of oxygen to the mass of hydrogen in hydrogen peroxide is

$\pink{ \frac{94.07}{5.93} = 15.86}$

For water, 100 g of sample will contain 11.2 g hydrogen and 100−11.2=88.8 g oxygen respectively.

The ratio of the mass of oxygen to the mass of hydrogen in hydrogen peroxide is

$\pink{ \frac{88.8}{11.2} = 7.93}$

The two ratios are in the proportion

$\pink{\frac{15.86}{7.93} = 2 : 1}$

Hence, this illustrates the Law of multiple proportions. According to this law, if two elements chemically combine with each other forming two or more compounds with different compositions by mass then the ratios of masses of two interacting elements in the two compounds are small whole numbers.