Question

hydrogen and oxygen are known to form two compounds the hydrogen content in one of these is 59.3%while in the other it is 11.2% Show that the given data illustrate the law of multiple proportions
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Answer 1

Answer:

The hydrogen content in one one of these is 5.93% while in the other it is 11.2%. ... The ratio of masses pf oxygen that combine with fixed mass (1 part) by mass of hydrogen is 15.86 : 7.9 or 2 : 1. Since this ratio is a simple whole number ratio, hence the given data illustrates the law of multiple proportions.

Explanation:

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Answer 2

Answer:

Compound with hydrogen content 11.2% is water(H₂O)

Explanation:

In chemistry, the law of multiple proportions states that if two elements form more than one compound, then the ratios of the masses of the second element which combine with a fixed mass of the first element will always be ratios of small whole numbers.

In compound 2, percent composition of hydrogen is 11.2% so percent composition of oxygen will be 88.8%.

Empirical formula of compound 2:

1.Dividing percent composition by atomic mass

H⇒ $\frac{11.2}{1}$= 11.2

O⇒$\frac{88.8}{16}$=5.55

2.Dividing the obtained quotients by the smaller quotients

H⇒$\frac{11.2}{5.55}$=2.02≈2

O⇒$\frac{5.55}{5.55}$=1

∴H:O=2:1, so empirical formula of compound 2 is H₂O.

Similarly, the empirical formula of coumpound 1 is found out.The empirical formula of compound 1 (H=59.3%,O=40.7%) is H₂₃O.(P.S: I'm not sure if that's an actual compound but according to the percent composition,this is the compound).

Since the elements H & O form more than one compound,the ratios of the masses of the second element which combine with a fixed mass of the first element  are ratios of small whole numbers; 23:1 and 2:1 for coumpound 1 & 2 respectively.

Therefore,the given data illustrate the law of multiple proportions.